Charas Pub

[Moosetroop11]

MT11: 0_o Where'd the evil army go?

[Razor]

Leader: Right beehind yoo.
MT11: Ahh! Oh. *drinks*

[Big_Duke]

*Duke Returns*
Duke:BEHOWELD!I HAVE SEEN KENNY!

Razor:WTF?!

Dragonium:Hi!

[Dragonium]

Dragonium: You spelt "Behold" wrong.

Duke: Thanks for ruining my fun. *Walks out*

[Razor]

Darkfox: I AM A TRIANGLE.
Darkfox: I never said that!
Darkfox: Sure you did!
Darkfox: Meh. *takes a drink*







asterisks: but since darkfox doesn't drink, he is actually drinking strawberry Quik.

[Moosetroop11]

MT11: Too pointless...

[Razor]

Assman: BUT NOT POINTLESS ENOUGH!
Pointy: Don't you have a job to do?
Assman: ...I got fired. *drinks*

[Dragonium]

*Cloud walks in wearing a tutu and a bowler hat*

Ultros: Vwoo hoo hoo.

Cloud: *Bashes Ultros with a paperclip*

[WarxePB]

-Warxe: *bad dubbing* Yay for randomness!

*He starts dancing*

-Odin: *bad dubbing* Your dancing infuriates me! *rips his armor off like cloth and transforms into the Hulk*

-Kratos: ?

-Odin: GRRRR! ODIN SMASH! *smashes a table in*

-Razor: You're paying for that!

-Odin: ODIN PAY! *grabs his wallet and pays Razor*

-Morionn: ...

-Kratos: I've had enough of this. *tries to walk out, but there's a steel door and bars over the exit*

-Razor: No one leaves!

-Kratos: *jumps through the open window*

-Razor: D'oh!

-Odin: ODIN GET! *runs through the wall, and starts chasing Kratos*

[Dragonium]

Dragonium: Buzzz. *Transforms into Prof. Drag*

Prof. Drag: Now then... Any questions?

Drace: How much would would a Woodchuck chuck if a Woodchuck could chuck wood?

Prof.: Well, given a reasonable chucking distance of 1m, and a Woodchuck of average mass - shall we say, 3.3kg - the maximum possible energy a Woodchuck could expend is simple to calculate.

*Writing on a blackboard at light speed*

Prof.: E=mc2, which is equal to
E=3.3*(3*10^8)2=2.97*1017, and the minimum velocity required being equal to
S=ut+0.5at2, and, being that any object achieves maximum velocity at 45 degrees, we can see that
(1,0)=(2-0.5)(V,V)+0.5(o,-9.(t2);
(2-0.5)=V=0.707. Now we can calculate a solution.
E=1/2mv2, and as we are looking for m, we need to calculate
2.97*1017=0.5*m*(0.7072)
And we can now see that approximately 1018kg of wood could be chucked by a Woodchuck working at maximum velocity. However, this sort of mad chucking would annihilate the Woodchuck in the process, so this is ethically a less than clear-cut question. We could increase the limit by allowing the Woodchuck to eat over a given time; however, this is by a negligible magnitude, which I shall not consider here. Note that considering the size of a Woodchuck, we can reduce the distance to half a metre, and it would still be considered a chuck. Now, any questions?

Drace: O_o *Brain implodes*

Dragonium: Bzzz. *Reverts back to normal*

[Moosetroop11]

Dragonium: *Looks around, everyone's brain has imploded* What?

[Dragonium]

Dragonium: Hmm... The perfect opportunity... *Does the Mr. Burns "Excellent"*

*Sneaks over to the bar, starts drinking the beer out of the tap*

Razor: *Comes up stairs* Sorry, I was changing a barrel. What did I miss?

Dragonium: ...

Razor: ... *Slowly picks up mallet*

Dragonium: Noooooo! *Casts Random Crappy Magic Attack*

Razor: *Synchronisation with lip movements is way out* What the hell does that do?

Dragonium: *Synchronisation is out* Sorry, it does that from time to time.

Razor: Friends?

Dragonium: Friends. *Both shake hands, Dragonium turns around to walk away*

*Thunk*

Dragonium: O_o *Falls over*

Razor: *Plays with mallet* Hehehehe... Excellent...

[Grandy]

Grandy: You should not do that.
Razor: Your brain imploded!
Grandy: I have no brain

[Darkfox]

Kitsune: *Curiously* Rrrrrealy...!?

Darkfox: You know, alot of what you said Dragonium was gobbledygook! Psychosis if you will...

Psychosis: The question was "How much wood chuck chuck if a wood chuck could chuck wood". If we are referring to the mammal which is of relation to the beaver I will say that they would not chuck but rather roll the wood. Of course it depends on the size and weight of the woodchuck and if he has assistance. So we could say it's h times w equaling d. H being height, w being weight and d is the distance in which the wood is rolled. The product of the multiplier will of course be converted in a further process to somthing more understandable, like feet, let me demonstrate...
Lets say a woodchuck is... 3 feet tall and weighs 65 pounds. That equals of course 195... divideing by 15 would equal 13. Therefor using that we could assume 13 is feet per hour. Though this isn't completely correct math it could be used as an example. Any questions?

[Grandy]

Grandy: *Reaise up hand* I have one! Wasn't that a retorical question?